-16x^2+24x+4=0

Solution for -16x^2+24x+4=0 equation:

-16x^2+24x+4=0

a = -16; b = 24; c = +4;
Δ = b2-4ac
Δ = 242-4·(-16)·4
Δ = 832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{832}=\sqrt{64*13}=\sqrt{64}*\sqrt{13}=8\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8\sqrt{13}}{2*-16}=\frac{-24-8\sqrt{13}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8\sqrt{13}}{2*-16}=\frac{-24+8\sqrt{13}}{-32}
$